線上遊戲排行榜2013/2014,進擊的巨人線上看,candy crush saga外掛,正妹寫真三圍

Jun 14th 2014, 08:56, by wxtab019

作者wxtab019 (天霜凝月)

看板ask

標題Re: [請問] 一題電路求負載的問題

時間Sat Jun 14 08:56:11 2014

※ 引述《kattte (誠實面對自己吧!)》之銘言： : -----------R2---[+ 50V -]----------------- : | | | | | : | 電 7ma | | | : R1 流 向下 R3 R4 RL : | 源 | | | : | | | | | : --------------------------------[+ 20V -]- : All resistors are 3.3k ohm. : Use the The'venin equivalent to find V(RL). : 用線上模擬電路跑的結果是 2.98v : 可是我算了好幾次都差很多 @@ : 不知道該怎麼算? ----------R2---[+ 50V -]----------------- | | | | | | 電 7ma | | | R1 流 向下 R3 R4 RL | 源 | | | | | | | | --------------------------------[+ 20V -]- ================================================= 先電流源轉電壓源 ----------R2---[+ 50V -]----------------- | | | | |- | | | 電壓源=3.3k ohm*7mA R3 R4 RL |+ =23.1V | | | | | | | -------R1-----------------------[+ 20V -]- =================================================== 合併50V和23.1V R1 R2 ----------------------------------------- | | | | |- | | | 電壓源=23.1+50V R3 R4 RL |+ =73.1V | | | | | | | -------R1+R2-------------------[+ 20V -]- =6.6k ohm ===================================================== 再變回電流源=73.1/6.6=11.076mA ----------------------------------------- | | | | | | | | | | ↓11.076mA R1+R2 R3 R4 RL | | | | | | | | | | --------------------------------[+ 20V -]- =================================================== R1~R4並聯=1.32k ohm 再轉成電壓源 Vall=11.076*1.32=14.62V ----------------------------------------- | | |- | 14.62V RL |+ | | | ------Rall----------------[+ 20V -]- Vout=14.62-20=-5.38V -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 140.123.222.30 ※ 文章網址: http://www.ptt.cc/bbs/ask/M.1402707374.A.870.html

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